What is the x-intercept of the graph of y = -15x + 60 in the xy-plane?
GMAT Algebra : (Alg) Questions
What is the x-intercept of the graph of \(\mathrm{y = -15x + 60}\) in the xy-plane?
1. TRANSLATE the problem information
- Given: Linear equation \(\mathrm{y = -15x + 60}\)
- Need to find: x-intercept of the graph
- Key insight: The x-intercept is where the graph crosses the x-axis, which means \(\mathrm{y = 0}\)
2. TRANSLATE the x-intercept condition
- Set \(\mathrm{y = 0}\) in the equation: \(\mathrm{0 = -15x + 60}\)
- This gives us a linear equation to solve for x
3. SIMPLIFY to solve for x
- Starting with: \(\mathrm{0 = -15x + 60}\)
- Add 15x to both sides: \(\mathrm{15x = 60}\)
- Divide both sides by 15: \(\mathrm{x = 4}\)
4. Express as coordinate point
- The x-intercept occurs at \(\mathrm{x = 4}\)
- Since we're on the x-axis, \(\mathrm{y = 0}\)
- Therefore, the x-intercept is \(\mathrm{(4, 0)}\)
Answer: C. (4, 0)
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE skill: Confusing x-intercept with y-intercept
Students sometimes think "intercept" means where the line crosses the y-axis, so they look for the y-intercept instead. In \(\mathrm{y = -15x + 60}\), when \(\mathrm{x = 0}\), we get \(\mathrm{y = 60}\).
This leads them to select Choice B. \(\mathrm{(0, 60)}\)
Second Most Common Error:
Poor SIMPLIFY execution: Making sign errors during algebraic manipulation
When solving \(\mathrm{0 = -15x + 60}\), students might subtract 60 from both sides to get \(\mathrm{-60 = -15x}\), then divide by -15 incorrectly, getting \(\mathrm{x = -4}\) instead of \(\mathrm{x = 4}\).
This may lead them to select Choice A. \(\mathrm{(-4, 0)}\)
The Bottom Line:
The key challenge is correctly TRANSLATING what "x-intercept" means (\(\mathrm{y = 0}\)) rather than confusing it with y-intercept (\(\mathrm{x = 0}\)). Once that translation is correct, the algebra is straightforward.