In the xy-plane, line L has equation y = -3x + 7. Line k is the vertical line with equation...
GMAT Algebra : (Alg) Questions
In the xy-plane, line L has equation \(\mathrm{y = -3x + 7}\). Line k is the vertical line with equation \(\mathrm{x = -2}\). What is the point of intersection of lines L and k?
- \(\mathrm{(-2, -13)}\)
- \(\mathrm{(-2, 1)}\)
- \(\mathrm{(-2, 6)}\)
- \(\mathrm{(-2, 13)}\)
1. TRANSLATE the problem information
- Given information:
- Line L has equation \(\mathrm{y = -3x + 7}\)
- Line k is vertical with equation \(\mathrm{x = -2}\)
- What we need: The intersection point of these two lines
2. INFER the solution approach
- At an intersection point, both equations must be satisfied simultaneously
- Since line k tells us \(\mathrm{x = -2}\), we can substitute this x-value directly into line L's equation
- This will give us the y-coordinate of the intersection point
3. SIMPLIFY by substituting and calculating
- Substitute \(\mathrm{x = -2}\) into \(\mathrm{y = -3x + 7}\):
- \(\mathrm{y = -3(-2) + 7}\)
- \(\mathrm{y = 6 + 7}\)
- \(\mathrm{y = 13}\)
- The intersection point is \(\mathrm{(-2, 13)}\)
Answer: D
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak SIMPLIFY execution: Sign error when computing \(\mathrm{-3(-2)}\)
Students often incorrectly calculate \(\mathrm{-3(-2) = -6}\) instead of +6. This leads to:
\(\mathrm{y = -6 + 7 = 1}\)
This may lead them to select Choice B (\(\mathrm{(-2, 1)}\))
Second Most Common Error:
Incomplete SIMPLIFY execution: Stopping the calculation too early
Some students correctly find \(\mathrm{-3(-2) = 6}\) but then forget to add the constant term, thinking the answer is just 6.
This may lead them to select Choice C (\(\mathrm{(-2, 6)}\))
The Bottom Line:
This problem tests careful arithmetic execution more than conceptual understanding. The setup is straightforward, but sign errors and incomplete calculations are the main pitfalls.