A quantity y varies inversely with w, so y = k/w for a constant k (where w neq 0).The constant...
GMAT Advanced Math : (Adv_Math) Questions
- A quantity \(\mathrm{y}\) varies inversely with \(\mathrm{w}\), so \(\mathrm{y = \frac{k}{w}}\) for a constant \(\mathrm{k}\) (where \(\mathrm{w \neq 0}\)).
- The constant \(\mathrm{k}\) equals \(\mathrm{-54}\).
- When \(\mathrm{y = 6}\), what is the value of \(\mathrm{w}\)?
1. TRANSLATE the problem information
- Given information:
- y varies inversely with w: \(\mathrm{y = k/w}\)
- The constant \(\mathrm{k = -54}\)
- When \(\mathrm{y = 6}\), find w
- This means we substitute these values into our inverse variation equation
2. TRANSLATE into a solvable equation
- Substitute the known values into \(\mathrm{y = k/w}\):
\(\mathrm{6 = -54/w}\)
- Now we have a simple algebraic equation to solve
3. SIMPLIFY to isolate w
- Multiply both sides by w to eliminate the fraction:
\(\mathrm{6w = -54}\)
- Divide both sides by 6:
\(\mathrm{w = -54/6 = -9}\)
4. Verify the answer
- Check: If \(\mathrm{w = -9}\), then \(\mathrm{y = -54/(-9) = 6}\) ✓
Answer: -9
Why Students Usually Falter on This Problem
Most Common Error Path:
Poor SIMPLIFY execution with negative numbers: Students often struggle with the sign when dividing -54 by 6, or they might incorrectly handle the negative signs throughout the algebraic manipulation. For example, they might get \(\mathrm{w = 9}\) instead of \(\mathrm{w = -9}\), forgetting that \(\mathrm{-54 ÷ 6 = -9}\).
This confusion with negative number operations can lead to selecting the wrong answer or getting stuck.
Second Most Common Error:
Weak TRANSLATE reasoning: Some students set up the equation incorrectly, such as writing \(\mathrm{6 = w/(-54)}\) instead of \(\mathrm{6 = -54/w}\), because they misunderstand how to substitute values into the inverse variation formula.
This incorrect setup leads to solving the wrong equation entirely and getting an incorrect answer.
The Bottom Line:
Success on this problem requires careful attention to negative signs and accurate substitution into the inverse variation formula. The algebraic manipulation is straightforward once the equation is set up correctly.