How many solutions does the equation \(\frac{\mathrm{y}+6}{2} = \frac{3\mathrm{y}}{2} - (\mathrm{y}-1)\) have?
GMAT Algebra : (Alg) Questions
How many solutions does the equation \(\frac{\mathrm{y}+6}{2} = \frac{3\mathrm{y}}{2} - (\mathrm{y}-1)\) have?
Exactly one
Exactly two
Infinitely many
Zero
1. SIMPLIFY by eliminating fractions
- Multiply every term by 2 (the LCD of the fractions):
- \(2 \cdot \frac{y+6}{2} = 2 \cdot \frac{3y}{2} - 2 \cdot (y-1)\)
- This gives us: \(y + 6 = 3y - 2(y-1)\)
2. SIMPLIFY the right side using distribution
- Apply distributive property to \(-2(y-1)\):
- \(-2(y-1) = -2y + 2\)
- Now we have: \(y + 6 = 3y - 2y + 2\)
3. SIMPLIFY by combining like terms
- Combine \(3y - 2y\) on the right side:
- \(y + 6 = y + 2\)
4. SIMPLIFY further by isolating constants
- Subtract \(y\) from both sides:
- \(6 = 2\)
5. INFER the meaning of this result
- The statement \(6 = 2\) is never true - it's a contradiction
- When solving an equation leads to a contradiction, the original equation has no solutions
Answer: D) Zero
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak SIMPLIFY execution: Students make sign errors when distributing the negative, particularly with \(-2(y-1)\). They might incorrectly get \(-2y - 2\) instead of \(-2y + 2\), leading to a different final equation like \(y + 6 = y - 2\), which would give \(6 = -2\) (still a contradiction, but they might not recognize it correctly).
This computational error can cause confusion about what the final result means, leading them to select Choice A (Exactly one) if they think they made a simple mistake.
Second Most Common Error:
Poor INFER reasoning: Students correctly reach \(6 = 2\) but don't understand what a contradiction means in the context of equation solving. They might think this means there's some solution they missed or that they should try a different approach.
This conceptual gap leads to confusion and guessing among the remaining choices.
The Bottom Line:
This problem tests whether students can execute a complete algebraic simplification AND interpret what contradictions mean. Many students can do the algebra but struggle with the conceptual leap that "impossible statement = no solutions."
Exactly one
Exactly two
Infinitely many
Zero