prismlearning.academy Logo
NEUR
N

In 2008, Zinah earned 14% more than in 2007, and in 2009 Zinah earned 4% more than in 2008. If...

GMAT Problem-Solving and Data Analysis : (PS_DA) Questions

Source: Practice Test
Problem-Solving and Data Analysis
Percentages
HARD
...
...
Notes
Post a Query

In \(\mathrm{2008}\), Zinah earned \(\mathrm{14\%}\) more than in \(\mathrm{2007}\), and in \(\mathrm{2009}\) Zinah earned \(\mathrm{4\%}\) more than in \(\mathrm{2008}\). If Zinah earned \(\mathrm{y}\) times as much in \(\mathrm{2009}\) as in \(\mathrm{2007}\), what is the value of \(\mathrm{y}\)?

A

\(\mathrm{0.5600}\)

B

\(\mathrm{1.0056}\)

C

\(\mathrm{1.1800}\)

D

\(\mathrm{1.1856}\)

Solution

1. TRANSLATE the problem information

  • Given information:
    • 2008 earnings: 14% more than 2007
    • 2009 earnings: 4% more than 2008
    • Need to find: \(\mathrm{y}\) where \(\mathrm{2009 = y \times 2007}\)
  • What this tells us: We need to track how earnings change through each year, then compare 2009 to the original 2007 amount.

2. TRANSLATE percentage increases into multipliers

  • 14% increase means \(\mathrm{new\ amount = 1.14 \times original\ amount}\)
  • 4% increase means \(\mathrm{new\ amount = 1.04 \times original\ amount}\)

3. Set up variables and equations

  • Let \(\mathrm{A}\) = Zinah's 2007 earnings
  • 2008 earnings = \(\mathrm{1.14A}\) (14% more than 2007)
  • 2009 earnings = \(\mathrm{1.04 \times (2008\ earnings) = 1.04 \times 1.14A}\)

4. SIMPLIFY to find the relationship

\(\mathrm{2009\ earnings = 1.04 \times 1.14A}\)

Calculate: \(\mathrm{1.04 \times 1.14 = 1.1856}\) (use calculator)

So \(\mathrm{2009\ earnings = 1.1856A}\)

5. Find y

Since \(\mathrm{2009 = y \times 2007}\): \(\mathrm{1.1856A = y \times A}\)

Therefore: \(\mathrm{y = 1.1856}\)

Answer: D. 1.1856




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak TRANSLATE skill: Students incorrectly think they can simply add the percentages together: \(\mathrm{14\% + 4\% = 18\%}\), so \(\mathrm{y = 1.18}\).

This reasoning misses that the 4% increase applies to the already-increased 2008 amount, not the original 2007 amount. The increases compound rather than simply add.

This leads them to select Choice C (1.1800).

Second Most Common Error:

Poor SIMPLIFY execution: Students correctly set up the problem as \(\mathrm{1.14 \times 1.04}\) but make calculation errors with the decimal multiplication.

Common mistakes include getting 1.0056 (possibly from \(\mathrm{1.14 \times 0.04}\)) or other decimal errors that don't result in the correct product.

This may lead them to select Choice B (1.0056) or causes confusion and guessing.

The Bottom Line:

This problem requires understanding that percentage increases compound (multiply) rather than simply add together, combined with careful decimal arithmetic to avoid calculation errors.

Answer Choices Explained
A

\(\mathrm{0.5600}\)

B

\(\mathrm{1.0056}\)

C

\(\mathrm{1.1800}\)

D

\(\mathrm{1.1856}\)

Rate this Solution
Tell us what you think about this solution
...
...
Forum Discussions
Start a new discussion
Post
Load More
Similar Questions
Finding similar questions...
Previous Attempts
Loading attempts...
Similar Questions
Finding similar questions...
Parallel Question Generator
Create AI-generated questions with similar patterns to master this question type.